本文共 2323 字，大约阅读时间需要 7 分钟。
| Time Limit: 1000MS | | Memory Limit: 30000K |
| Total Submissions: 15948 | | Accepted: 6887 |
Description
A prefix of a string is a substring starting at the beginning of the given string. The prefixes of "carbon" are: "c", "ca", "car", "carb", "carbo", and "carbon". Note that the empty string is not considered a prefix in this problem, but every non-empty string is considered to be a prefix of itself. In everyday language, we tend to abbreviate words by prefixes. For example, "carbohydrate" is commonly abbreviated by "carb". In this problem, given a set of words, you will find for each word the shortest prefix that uniquely identifies the word it represents.
In the sample input below, "carbohydrate" can be abbreviated to "carboh", but it cannot be abbreviated to "carbo" (or anything shorter) because there are other words in the list that begin with "carbo".
An exact match will override a prefix match. For example, the prefix "car" matches the given word "car" exactly. Therefore, it is understood without ambiguity that "car" is an abbreviation for "car" , not for "carriage" or any of the other words in the list that begins with "car".
Input
The input contains at least two, but no more than 1000 lines. Each line contains one word consisting of 1 to 20 lower case letters.
Output
The output contains the same number of lines as the input. Each line of the output contains the word from the corresponding line of the input, followed by one blank space, and the shortest prefix that uniquely (without ambiguity) identifies this word.
Sample Input
carbohydratecartcarburetorcaramelcariboucarboniccartilagecarboncarriagecartoncarcarbonate
Sample Output
carbohydrate carbohcart cartcarburetor carbucaramel caracaribou caricarbonic carbonicartilage carticarbon carboncarriage carrcarton cartocar carcarbonate carbona 题解：让找唯一能确定一个单词的前缀；我们想到当唯一确定的时候必定word[k]是1；那么很好解决了 代码：
1 #include 2 #include 3 #include 4 #include 5 #include 6 #include 7 #define mem(x,y) memset(x,y,sizeof(x)) 8 using namespace std; 9 typedef long long LL;10 const int MAXN=10100;11 char s[1010][30];12 int ch[MAXN][30],word[MAXN];13 int sz;14 void initial(){15 sz=1;16 mem(word,0);17 }18 void insert(char *s){19 int len=strlen(s);20 int j,k=0;21 for(int i=0;i
转载地址：http://nueaz.baihongyu.com/